Answer:
64 terabytes
Explanation:
Given data:
Size of the disk block = 8 KB
Size required by the pointer to a disk block = 4 bytes
Now,
Size required by 12 direct disk blocks = 12 × 8
Size required by single disk block = 2048 × 8 KB
Size required by double disk block = 2048 × 2048 × 8 KB
size required by triple disk block = 2048 × 2048 × 2048 × 8 KB
Now,
the maximum size of the file that can be stored in the this file system = 12 × 8 + 2048 × 8 KB + 2048 × 2048 × 8 KB + 2048 × 2048 × 2048 × 8 KB = 64 terabytes
