She has 1 quarter, 1 dime and 13 nickels. So the probability that one coin at random is a nickel is 13/15.
My work:
1$= 100
1 quarter=25
1 dime=10
1+1+13= 15
25×1= 25
10×1= 10
5×13= 65
65+25+10= 100
Answer:
bottom right
Step-by-step explanation:
it goes down consitantly by 2
Answer:
81 square inches.
Step-by-step explanation:
Draw a diagram to represent what you know.
You don't know the values of the lengths so represent them algebraically.
You know the perimeter is 45 inches and that the perimeter is calculated by the sum of all of the sides of a shape.
You can rearrange to find the value of a side you've denoted as some unknown variable.
The area is given by the product of the sides. Express this algebraically and then input the value you found.
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
