1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
3 years ago
12

Write 4 with denominator 5

Mathematics
1 answer:
valkas [14]3 years ago
4 0

Answer:

4/5

Step-by-step explanation:

I'm not exactly sure what this question is asking but I'm guessing it's asking to create a fraction with the numerator as 4 and denominator as 5.

You might be interested in
1. What is the value of x?
lara31 [8.8K]
Is there any option to choose from ?

If so show them and I’ll probably be able to answer .
6 0
2 years ago
Can someone please answer if itś right I will give the brainlist thing
deff fn [24]

Answer:

the answer would be 116.

This is because if half of the kernels popped you just multiply 58 by 2 to get 100 percent of the kernels.

I hope this helps! Please mark me Brainliest!

Step-by-step explanation:

4 0
3 years ago
The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665. Using a table of values,
tamaranim1 [39]

Answer:

Option A. 5

Step-by-step explanation:

From the question given above, the following data were obtained:

First term (a) = –3

Common ratio (r) = 6

Sum of series (Sₙ) = –4665

Number of term (n) =?

The number of terms in the series can be obtained as follow:

Sₙ = a[rⁿ – 1] / r – 1

–4665 = –3[6ⁿ – 1] / 6 – 1

–4665 = –3[6ⁿ – 1] / 5

Cross multiply

–4665 × 5 = –3[6ⁿ – 1]

–23325 = –3[6ⁿ – 1]

Divide both side by –3

–23325 / –3 = 6ⁿ – 1

7775 = 6ⁿ – 1

Collect like terms

7775 + 1 = 6ⁿ

7776 = 6ⁿ

Express 7776 in index form with 6 as the base

6⁵ = 6ⁿ

n = 5

Thus, the number of terms in the geometric series is 5.

8 0
3 years ago
(x+2)(x+5) find the following products by using distributive property
nika2105 [10]

Answer:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(

x

+

5

)

(

x

+

2

)

becomes:

(

x

×

x

)

+

(

x

×

2

)

+

(

5

×

x

)

+

(

5

×

2

)

x

2

+

2

x

+

5

x

+

10

We can now combine like terms:

x

2

+

(

2

+

5

)

x

+

10

x

2

+

7

x

+

10

Step-by-step explanation:

7 0
3 years ago
Traffic along a stretch of road moves at an average speed that varies inversely with the number of cars on it. When there are 15
RSB [31]

Answer:

37.5 miles per hour

Step-by-step explanation:

The traffic along a stretch road moves at an average speed that carried inversely as the number of cars

Average speed= k/number of cars.

When there are 1,500 cars the average speed is 45

The first step is to calculate the constant k

45= k/1500

k = 1,500 × 45

k= 67,500

Therefore the average speed when there are 1,800 cars can be calculated as follows

Average speed= 67,500/1,800

= 37.5 miles per hour

Hence the average speed is 37.5 moles per hour

7 0
3 years ago
Other questions:
  • A rectangular paperboard measuring 20in long and 16in wide has a semicircle cut out of it, as shown below.Find the area of the p
    9·1 answer
  • zoe wrote 3/5 of her essay in 30 minutes. assuming she wrote the paper at a constant rate the entire time, which expression can
    15·2 answers
  • Find the difference. Simplify. Combine Like Terms.
    10·1 answer
  • The Long family spent $38.62 for school supplies and $215.78 for new school clothes. They paid sales tax on their purchases. If
    11·1 answer
  • Simple Interest and Compound Interest.<br>Guys I need help with this question.
    5·1 answer
  • ILL MARK BRAINLIEST IF YOU HELP MEEE!
    9·2 answers
  • Can anyone show me how to figure this out.
    15·1 answer
  • What are the potential solutions of
    15·1 answer
  • Which quadrilateral and why?
    6·1 answer
  • HELP ME OUTT PPL (BRAINIEST)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!