Dat be called common difference represented by d in the equation
90 is the outlier
for future reference, outliers are numbers much larger or much smaller than the other numbers in a set
for example
2,3,4,21,6
or 90,87,94,12,99
You may need to sit down with your parents or with your teacher and
go over how to add and subtract fractions.
1). "Perimeter" means the distance all the way around the square.
With a square, all 4 sides are the same length. With <u>this</u> square,
every side is 1-1/4 inches long.
Perimeter = length of all 4 sides= (1-1/4) + (1-1/4) + (1-1/4) + (1-1/4) =
(1 + 1 + 1 + 1) + (1/4 + 1/4 + 1/4 + 1/4) =
4 + 4/4 = <em>5 inches</em> .
2). (2-3/8) + (1-7/8) = (2 + 1) + (3/8 + 7/8) =
(3) + (10/8) =
3 + 1-1/4 = <em>4-1/4 .</em>
3). The difference is (1-1/6) minus (5/6) .
Before you start to do the subtraction, write the (1-1/6) as (7/6) .
Then the subtraction is (7/6) - (5/6) = 2/6 = <em>1/3</em> .
4). This one is almost the same kind of problem as #3.
It's another subtraction.
If you need (2-1/4) all together, and you already have (1-3/8),
then the amount you still have to find, or borrow, or buy, is the
difference between those two numbers.
(2-1/4) minus (1-3/8) .
The trick is to write the (2-1/4) in some form that you'll be able to
subtract (1-3/8) from it. When I learned how to do that, it was called
'borrowing', but I think now it's called 'regrouping'.
We need to work on (2-1/4):
-- take 1 from the 2, and change it into fourths.
2-1/4 = 1 and 4/4 and 1/4 = 1 and 5/4
-- Now, take those 5/4, and turn them into eighths.
Each fourth makes 2 eighths. So 5/4 = 10/8.
Now, the (2-1/4) has turned into 1-10/8 .
We did NOT change the value. It's still the same amount
as 2-1/4 , but it's just written in a different way.
And now the subtraction is easy:
(2-1/4) minus (1-3/8) =
(1-10/8) minus (1-3/8) = (zero and 7/8).
You need <em>7/8 inch</em> more string than you already have.
Answer:
Tamara's example is in fact an example that represents a linear functional relationship.
- This is because the cost of baby-sitting is linearly related to the amount of hours the nany spend with the child: the more hours the nany spends with the child, the higher the cost of baby-sitting, and this relation is constant: for every extra hour the cost increases at a constant rate of $6.5.
- If we want to represent the total cost of baby-sitting in a graph, taking the variable "y" as the total cost of baby-sitting and the variable "x" as the amount of hours the nany remains with the baby, y=5+6.5x (see the graph attached).
- The relation is linear because the cost increases proportionally with the amount of hours ($6.5 per hour).
- See table attached, were you can see the increses in total cost of baby sitting (y) when the amount of hours (x) increases.
