Use limits to find the area of the region bounded by the graph f(x)=4-2x^3 , the x-axis , and the vertical lines x=0 and x=1
1 answer:
Answer:
square units.
Step-by-step explanation:
We have to use limits to find the area of the region bounded by the graph
, the x-axis, and the vertical lines x=0 and x=1.
So, the area will be
A = 
= ![[4x - \frac{x^{4}}{2} ]^{1} _{0}](https://tex.z-dn.net/?f=%5B4x%20-%20%5Cfrac%7Bx%5E%7B4%7D%7D%7B2%7D%20%5D%5E%7B1%7D%20_%7B0%7D)
= 
=
square units. (Answer)
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Answer:
Step-by-step explanation:
You are to take the square root across the inequality sign to make it plus or minus 3 squared.
The answer will therefore be C
x - y = 3
x = 3 + y
x -3 = y
y = x-3
put it in 1st equation
2x +y = 15
2x + x - 3 = 15
3x - 3 = 15
3x = 15+3 = 18
x = 18/3 = 6
x = 6
To start set up a fraction with the f(x) on top and g(x) on bottom
(f/g)(x) = (4x - 4)/(x - 1) - This is the function that we are going to use
Plug in -4 for x
(f/g)(-4) = (4(-4) - 4)/(-4 - 1) = (-16 - 4)/(-5) = (-20)/(-5) = 4
So...
(f/g)(-4) = 4
Answer:
5m-8
Step-by-step explanation:
Step-by-step explanation:
5x−4=5
1 Add 44 to both sides.
5x=5+4
5x=5+4
2 Simplify 5+45+4 to 99.
5x=9
5x=9
3 Divide both sides by 55.
x=\frac{9}{5}
x=
5
9