Answer:
(See explanation for further details)
Step-by-step explanation:
The real expression is:

The general equation for the second-order polynomial is:

This condition must be observed for the case of a quadratic equation with equal roots:




The red area is the one which solves the system. In fact, we want the area which below both the parabola and the line (since the inequality features a
sign.
So, the point
is below the line but above the parabola (blue area), so it is not a solution.
The point
is above both the line and the parabola (white area), so it is not a solution.
The point
is below both the line and the parabola (red area), so it is a solution.
So, the point
is below the parabola but above the line (green area), so it is not a solution.
Answer:
√2' = t
Step-by-step explanation:
1 1/2s = 3/5t^2 + 1/3u^2; substitute known values
1 1/2 • 28 = 3/5 • t^2 + 1/3 • -6^2; simplify
42 = 3 • t^2 ÷ 5 + 1/3 • 36
42 = 3 • t^2 ÷ 5 + 12; apply property of subtraction of equality
42 – 12 = 3t^2 ÷ 5 + 12 – 12; simplify
30 = 3t^2 ÷ 5; apply property of multiplication of equality
30 • 5 = 3t^2 ÷ 5 • 5; simplify
6 = 3t^2; apply property of division of equality
6 ÷ 3 = 3t^2 ÷ 3; simplify
2 = t^2
√2' = t
the correct answer is y=2
Answer:
$432.00
Step-by-step explanation:
12 x 36 = 432