With a given parallel line and a given point on the line we can use the point-line method: y-y0=m(x-x0) where y=mx+k is the given line, and (x0,y0) is the given point.
Here m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by: L: y-5=-10(x-(-3))