Answer:
36÷3÷2÷3=2
Step-by-step explanation:
Answer:
Distance = 8.06
Step-by-step explanation:
We have to use the distance formula
.
coordinates of the first point
coordinates of the second point
To solve, plug the appropriate values into the formula.
Answer:
option B
Step-by-step explanation:
option B
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Answer:
P ( -1 < Z < 1 ) = 68%
Step-by-step explanation:
Given:-
- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :
u = 67.2
s.d = 4.6
- The random variable (X) that denotes standardized test scores following normal distribution:
X~ N ( 67.2 , 4.6^2 )
Find:-
What percent of the data fell between 62.6 and 71.8?
Solution:-
- We will first compute the Z-value for the given points 62.6 and 71.8:
P ( 62.6 < X < 71.8 )
P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )
P ( -1 < Z < 1 )
- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:
P ( -1 < Z < 1 ) = 68%
P ( -2 < Z < 2 ) = 95%
P ( -3 < Z < 3 ) = 99.7%
Answer:
Step-by-step explanation:
6x + 3y = 3 simplify by dividing both sides by 3 2x + y = 1
3x - y = 4 the 1st equation has a positive y, the 2nd has a negative y. Use elimination
to reduce them down to a single variable equation:
2x + y = 1
3x - y = 4
________
5x = 5 solve
X = 1 substitute back in to one of the original equations to find y
3x - y = 4
3(1) - y = 4
- y = 1
y = -1 (1,-1)