4*4-5*3-2x+6= -x-7/2 slope = 2
3 * 3 - 4 *2 -2x +1= - x - 2/2 slope = -2
2 + -2 = 0
Following are the solution parts for the given question:
For question A:
In the given question, we calculate
of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

Using the t table we calculate
When
of the confidence interval:
So
confidence interval for the mean weight of shipped homemade candies is between
.
For question B:

Here we need to calculate
confidence interval for the true proportion of all college students who own a car which can be calculated as

Using the Z-table we found
therefore
the confidence interval for the genuine proportion of college students who possess a car is
So
the confidence interval for the genuine proportion of college students who possess a car is between 
For question C:
- In question A, We are
certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams. -
In question B, We are
positive that the true percentage of college students who possess a car is between 0.28 and 0.34.
Learn more about confidence intervals:
brainly.in/question/16329412
<h3>step 1.</h3>
use graph paper.
<h3>step 2.</h3>
draw lines thru the graph wait go on my image above!
Answer:
Area of pathway = 10.375 unit²
Step-by-step explanation:
Given - Peter has built a gazebo, whose shape is a regular heptagon, with
a side length of 1 unit. He has also built a pathway around the
gazebo, of constant width 1 unit, as shown below.
To find - Find the area of the pathway.
Proof -
Central angle =
= 51.43°
Now,
Central angle / 2 =
= 25.71°
And
height =
= 1.038
Now,
Inner area of gazebo = 7·
·1·(1.038) = 3.634 unit²
Outer area of gazebo = (
)²·(3.364) = 14.009 unit²
∴ we get
Area of pathway = Outer area - Inner area
= 14.009 - 3.634
= 10.375 unit²
⇒Area of pathway = 10.375 unit²