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Sveta_85 [38]
2 years ago
10

What is p-1/4•3=-5/6

Mathematics
1 answer:
suter [353]2 years ago
4 0
-1/12
That’s what P is equal to I wish this could help
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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so
allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> y+12=x^{2}+x and x+y=3

Part 2) No solutions ----> y-15=x^{2}+4x and x-y=1

Part 3) solution [(-2,5),(3,-5)] ---> y+5=x^{2}-3x and 2x+y=1

Part 4) No solutions ---> y-6=x^{2}-3x and x+2y=2

Part 5) solution [(2,3),(8,9)] --->y-17=x^{2}-9x and -x+y=1

Part 6) solution [(-2,3),(7,-6)] --->y-15=-x^{2}+4x and x+y=1

Step-by-step explanation:

Part 1) we have

y+12=x^{2}+x ----> equation A

x+y=3 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)  

see the attached figure N 1

Part 2) we have

y-15=x^{2}+4x ----> equation A

x-y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs  

see the attached figure N 2

Part 3) we have

y+5=x^{2}-3x ----> equation A

2x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)  

see the attached figure N 3

Part 4) we have

y-6=x^{2}-3x ----> equation A

x+2y=2 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs    

see the attached figure N 4

Part 5) we have

y-17=x^{2}-9x ----> equation A

-x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)  

see the attached figure N 5

Part 6) we have

y-15=-x^{2}+4x ----> equation A

x+y=1 ----> equation B

Solve by graphing    

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)  

see the attached figure N 6

5 0
3 years ago
The third grade class collected coins for the week.Class one raised 34.00. Class two raised 45.00 .Class three raised 76.00.How
Troyanec [42]

Answer:

160 well it was 155 but u round up to 160

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Which of the following statements regarding the expansion of (x + y)^n are correct?
kompoz [17]

Answer:

A, B and D are true statements.

Step-by-step explanation:

We are given a binomial expansion

(x+y)^n=^nC_0x^ny^0+^nC_1x^{n-1}y^1+^nC_2x^{n-2}y^2+...........+^nC_nx^0y^n

(x+y)^n=x^n+nx^{n-1}y+^nC_2x^{n-2}y^2+...........nxy^{n-1}+y^n

Now we will check each option

Option A: The coefficients of x^n and y^n both equal 1.

If we see first and last term of the expansion, This statement is true.

Option B: For any term x^ay^b in the expansion, a + b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a+b = n-2+2=n

a+b=n is true statement.

Option C: For any term x^ay^b in the expansion, a - b = n.

Let we take 3rd term of expansion ^nC_2x^{n-2}y^2

Here, a=n-2 and b=2

If we do  a-b = n-2-2=n-4≠n

a-b=n is false statement.

Option D: The coefficients of x^ay^b and x^by^a are equal.

If we take second term from beginning and last of the expansion.

\text{Coefficient From beginning } nx^{n-1}y=n

\text{From last } nxy^{n-1}=n

This statement true.

8 0
3 years ago
The difference of 21 and 16​
pogonyaev

Answer:

5

Step-by-step explanation:

i think

6 0
3 years ago
1) A rectangular storage container with an open top is to have a volume of 15 m 3 . The length of its base is four times the wid
My name is Ann [436]

9514 1404 393

Answer:

  a) V = 4w²h

  b) SA = 4w² +10wh

  c) SA = 4w² +37.5/w

  d) C = 40w² +225/w

Step-by-step explanation:

The relevant formulas are ...

  V = LWH

  base area = LW

  lateral area = H(2(L+W))

__

a) The length is 4 times the width, so the volume is ...

  V = (4w)(w)(h)

  V = 4w²h

__

b) The total surface area is the sum of the base area and the lateral area:

  SA = base area + lateral area

  SA = (4w)(w) + 2h(4w +w)

  SA = 4w² +10wh

__

c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...

  15 = 4w²h

  h = 15/(4w²)

Then the surface area is ...

  SA = 4w² +10w(15/(4w²))

  SA = 4w² +37.5/w

__

d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:

  C = 10(4w²) +6(37.5/w)

  C = 40w² +225/w

4 0
3 years ago
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