Assuming PQRS is a parallelogram, we have PQ = RS, and angles S and R are supplementary so their measures sum to 180°.
So
5<em>x</em> = <em>x</em> + 12
4<em>x</em> = 12
<em>x</em> = 3
→ PQ = 5<em>x</em> = 15
and
12<em>z </em>° + 6<em>z</em> ° = 180°
18<em>z</em> ° = 180°
<em>z</em> = 180/18 = 10
→ m∠<em>S</em> = 12•10° = 120°
Answer:
The first our to the second hour
Answer:
The radius of the spherical tank is 12 meters
Step-by-step explanation:
In this question, we are tasked with calculating the radius of the spherical tank given the volume of air it can hold
Mathematically, the volume V of a sphere is 4/3 * pi * r^3
Thus, 7234.56 = 4/3 * 3.14 * r^3
7,234.56 = 4.19 * r^3
r^3 = 7234.56/4.19
r^3 = 1,728
r = cube root of 1,728
r = 12 meters
Answer:
thursday, Tuesday, monday, Wednesday
the answer would be 50.27m3
