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Mashutka [201]
3 years ago
13

Given: Line segment WZ is congruent to line segment YZ. Line segment WX is parallel to line segment ZY

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0
In your problem where states the given that a line segment Wz is congruent to line YZ. The line segment  WX is parallel to line segment ZY so the ask of the problems is to prove that WXZ is congruent triangle to triangle YZX nad the reason that prove that both angle is congruent is the the given where WZ and ZY is congruent so the both have the same size and the WX is parallel to ZY so it means that they are also, form that reason itself proves that both triangle are equal.
Andrew [12]3 years ago
6 0

Answer:

According to the hypothesis, both triangles shares XZ as one side in common. Similarly, by hypothesis we know that side WZ is congruent with YZ. So, until now, we have two congruent sides, we just need one more side congruent, or two corresponding angles congruent to demonstrate the congruence between triangles.

By hypothesis, side WX and ZY are parallel, and the side WZ is transversal to them, which forms alternate internal angles, which are congruent. Specifically, according to the parallels and the transversal, angle WXZ is congruent to YZW.

Therefore, triangles are congruent by Side-Side-Angle postulate.

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koban [17]

Answer:

3 45/55 or 3 9/11

Step-by-step explanation:

convert each term to an improper fraction

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dividing fractions is the same as multiply by reciprocal of the second term

42/5 x -5/11 = -210/55

7 0
3 years ago
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Darya [45]
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8 0
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klasskru [66]
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A single die is rolled. Find the probability of rolling an oddnumber or a number less than 6.
mina [271]

Given

A single die is rolled.

To find the probability of rolling an odd number or a number less than 6.

Explanation:

It is given that,

A single die is rolled.

Then, the sample space is,

\begin{gathered} S=\lbrace1,2,3,4,5,6\rbrace \\ n(S)=6 \end{gathered}

Let A be the event of getting an odd number.

Then,

\begin{gathered} A=\lbrace1,3,5\rbrace \\ n(A)=3 \end{gathered}

Let B be the event of getting a number less than 6.

Then,

\begin{gathered} B=\lbrace1,2,3,4,5\rbrace \\ n(B)=5 \end{gathered}

Also,

\begin{gathered} A\cap B=\lbrace1,3,5\rbrace \\ n(A\cap B)=3 \end{gathered}

Therefore,

\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{n(A\cap B)}{n(S)} \\ =\frac{3}{6}+\frac{5}{6}-\frac{3}{6} \\ =\frac{3+5-3}{6} \\ =\frac{5}{6} \end{gathered}

Hence, the answer is 5/6.

5 0
1 year ago
Read 2 more answers
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faust18 [17]
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8 0
3 years ago
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