Answer:
The simplyfied version would be 19/4
Show of work:
(1/4)^-2 = 4^2
3 × 8^2/3 × 1 = 12
(9/16)^1/2 = 3/4
4^2 - 12 + 3/4
Convert elements to fractions:
-12 × 4 + 3
---------- ----
4 4
Since the denominators are equal combine the fractions:
-12 × 4 + 3
---------------
4
-12 × 4 + 3 = -45
= -45/4
=4^2 - 45/4
4^2 = 16
16 - 45/4
16 × 4 - 45. 16 × 4 - 45
--------- ----- ----------------
4 4. 4
-> 16 × 4 - 45 = 19
= 19/4
Answer:
The complete solution is
Step-by-step explanation:
Given differential equation is
3y"- 8y' - 3y =4
The trial solution is
Differentiating with respect to x
Again differentiating with respect to x
Putting the value of y, y' and y'' in left side of the differential equation
The auxiliary equation is
The complementary function is
y''= D², y' = D
The given differential equation is
(3D²-8D-3D)y =4
⇒(3D+1)(D-3)y =4
Since the linear operation is
L(D) ≡ (3D+1)(D-3)
For particular integral
[since 
]
[ replace D by 0 , since L(0)≠0]
The complete solution is
y= C.F+P.I
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
The solution is in the attached file
