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valentinak56 [21]
4 years ago
13

A provincial park claims that the probability of spotting moose in the park is 0.15 and the probability of seeing loons is 0.70.

Mathematics
1 answer:
Ad libitum [116K]4 years ago
8 0

Answer:

A) 0.105

B) 0.30

C) 0.70

Step-by-step explanation:

The probability of spotting moose is 0.15.

The probability of spotting loons is 0.70.

A) The probability of spotting moose and loons on the same day is =

0.15 * 0.70 = 0.105

B) The probability of spotting moose on two consecutive days is:

2 * 0.15 = 0.30

C) The probability of not spotting moose for two days is:

1 - P(Moose on two consecutive days) = 1 - 0.30 = 0.70

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Step-by-step explanation:

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3 years ago
GUYS I NEED HELP ASAP
vovangra [49]

Answer:

A=2400ft

Step-by-step explanation:

A rectangle is a closed planer quadrilateral with four  right angles and its opposite sides are the same length. The fence around it including the gates is 200 feet long, so basically they are providing the perimeter of the rectangle. The perimeter of a rectangle is equal to the sum of all its sides. Hence:

Perimeter=w+h+w+h=2w+2h\\\\Where:\\\\w=Width\\h=Height

The ectangular playground is 40 feet wide, so:

w=40ft

Therefore:

Perimeter=2w+2h\\\\200=2(40)+2h\\\\200=80+2h

Solving for h:

2h=200-80\\\\2h=120\\\\h=\frac{120}{2} \\\\h=60ft

The area of a rectangle is equal to the product of two of its contiguous sides, hence:

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5 0
3 years ago
Need help with thisss
frozen [14]

9514 1404 393

Answer:

  cos(x) = 0.6

Step-by-step explanation:

First, we need to find UQ.

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Then TQ is ...

  TQ = 1/3UQ = 1/3(24 cm) = 8 cm

And cos(x°) is ...

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3 years ago
The results of a swim meet are shown. Who swam the fastest? Explain your reasoning.
kobusy [5.1K]

Answer : The Susana swam the fastest.

Step-by-step explanation :

Speed : It is defined as the distance traveled per unit time.

Formula used :

Speed=\frac{Distance}{Time}

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<u>For Tawni :</u>

Distance = 50 m

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The speed of Tawni is, 1.225 m/s

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The speed of Pepita is, 1.661 m/s

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The speed of Susana is, 1.779 m/s

From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.

Thus, Susana swam the fastest.

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