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LekaFEV [45]
3 years ago
13

Which of these equations have no solution? Check all that apply.

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

A. 2(x + 2) + 2 = 2(x + 3) + 1

B. 2x + 3(x + 5) = 5(x – 3)

E. 5(x + 4) – x = 4(x + 5) – 1

These answers are correct I took the test

Hope it helps!

Llana [10]3 years ago
3 0
2(x + 2) + 2 = 2(x + 3) + 1
2x + 4 + 2 = 2x + 6 + 1
2x + 6 = 2x + 7 - NO SOLUTION
(subtract 2x from both sides, then 6 = 7 FALSE)

2x + 3(x + 5) = 5(x – 3)
2x + 3x + 15 = 5x - 15
5x + 15 = 5x - 15 - NO SOLUTION

4(x + 3) = x + 12
4x + 12 = x + 12 - ONE SOLUTION

4 – (2x + 5) = (–4x – 2)
4 - 2x - 5 = -4x - 2
-2x - 1 = -4x - 2  - ONE SOLUTION

5(x + 4) – x = 4(x + 5) – 1
5x + 20 - x = 4x + 20 - 1
4x + 20 = 4x + 19 - NO SOLUTION




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Answer:

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Step-by-step explanation:

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6 0
3 years ago
The sum of liz's and melinda's ages is 28. if liz was 1/3 melinda's age 6 years ago, how old will liz be next year?
Mrrafil [7]
The first thing we must do for this case is to define variables:
 We have then:
 x: liz's age
 y: melinda's age
 We now write the system of equations:
 x + y = 28

x-6 = (1/3) (y-6)
 By solving the system graphically we have that the age of each one is currently:
 x = 10

 y = 18
 Next year, the age of liz is:
 x + 1 = 10 + 1 = 11

 Answer:
 
Next year, Liz's age is 11 years.
 
Note: see attached image for the graphic solution.

3 0
3 years ago
The sum of four times a number and five times another number is -28. The sum of nine times the first number and two times the se
Rina8888 [55]

Answer:

<h2>3 and -8</h2>

Step-by-step explanation:

x,\ y-the\ numbers\\\\\text{The sum of four times a number and five times another number is -28:}\\\\4x+5y=-28\\\\\text{The sum of nine times the first number and two times the second number is 11:}\\\\9x+2y=11\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}4x+5y=-28&\text{multiply both sides by2}\\9x+2y=11&\text{multiply both sides by (-5)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}8x+10y=-56\\-45x-10y=-55\end{array}\right}\qquad\text{add both sides of the equation}

.\qquad-37x=-111\qquad\text{divide both sides by (-37)}\\.\qquad\qquad\boxed{x=3}\\\\\text{Put the value of x to the first equation:}\\\\4(3)+5y=-28\\12+5y=-28\qquad\text{subtrac 12 from both sides}\\5y=-40\qquad\text{divide both sides by 5}\\\boxed{y=-8}

3 0
3 years ago
Let A and B be events in the sample space S, and let P[A]=.41, P[B]=.32 and LaTeX: P\left[B'\cap A\right]=.21. Find LaTeX: P\lef
Ivahew [28]

Answer:

P(A' ∩ B) = 0.12

Step-by-step explanation:

Given:

P(A) = 0.41, P(B) = 0.32 and P(B' ∩ A) = 0.21

To Find:

P(A' ∩ B)

Solution:

Since, P(B' ∩ A) = P(A) - P(A ∩ B)

By substituting the values given,

0.21 = 0.41 - P(A ∩ B)

P(A ∩ B) = 0.41 - 0.21

              = 0.20

Since, P(A' ∩ B) = P(B) - P(A ∩ B)

P(A' ∩ B) = 0.32 - 0.20

               = 0.12

Therefore, P(A' ∩ B) = 0.12 is the answer.

8 0
2 years ago
I NEED HELP RIGHT NOW WITH QUETIONS LIKE THIS parentehensees 5 to the second power close the parenthesees to the third power ple
yan [13]

Answer: Don't know sorry

Step-by-step explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET !

Bye Have a nice day:)

7 0
2 years ago
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