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nlexa [21]
3 years ago
8

Solve the system x-z=5, 2x+y= 7, y+3z=12

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0
x,z,y = 20,15,-33

i think thats it im sorry
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Bill drove 871 miles in 13 hours.
wariber [46]

Answer:

536 miles

Step-by-step explanation:

871/13 = 67

67*8 = 536

8 0
3 years ago
Read 2 more answers
A vial contains 20mL of medicine.If each dose is 1/3 of the vial,how many mL is each dose.Express your answer as a decimal
Genrish500 [490]

Answer:

each dose = 6.7 mL ( to 1 decimal place)

Step-by-step explanation:

Total volume of vial = 20mL

each dose of vial = 1/3 of the total volume

let us express this fraction as a real number:

1/3 of 20 = 1/3 × 20

Since we are to express the answer as a decimal, let us convert the fraction to decimal:

1/3 = 0.3333

∴ 1/3 × 20 = 0.3333 × 20 = 6.667 mL

since we are dealing with drugs, it'll be appropraite to express the answer to 1 d.p

∴ each dose = 6.7 mL

4 0
2 years ago
What is the maximum percent of net spendable income that should be set aside for housing
stepladder [879]

Answer:

Answer;


-38 %

Step-by-step explanation:

Explanation;


-Budget busters are the large potential problem areas that can destroy a budget. Failure to control even one of these problem areas can result in financial disaster.


-Housing takes about 38 percent of your monthly budget. Housing decisions should be based on need and financial ability, not on internal or external pressure.


-Food takes 12 percent of your monthly budget.  The reduction of a family's food bill requires quantity and quality planning.


-Transportation (purchase and maintenance), takes 15 percent of your monthly budget, Debts takes 5 percent of Net Spendable Income, Insurance takes 5 percent of Net Spendable Income assuming an employer provides medical insurance, Recreation/Entertainment takes 5 percent of Net Spendable Income, Clothing takes 5 percent of Net Spendable Income, Medical and dental takes 5 percent of Net Spendable Income and Savings takes 5 percent of Net Spendable Income

7 0
3 years ago
Read 2 more answers
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
Solve by graphing: y=3(x-2)^2-3
forsale [732]

Answer:

thank you !!!!

Step-by-step explanation:

6 0
3 years ago
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