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4 years ago

What is the solution to the system of equations {3x+2y+z=9;-3x-y+3z=-7;2x +z=9

Mathematics

2 answers:

icang [17]4 years ago

7 0

<span>Final answer: x = 1 ; y = -4 ; z = 3
</span>

Naily [24]4 years ago

7 0

Omg I hate doing math but I'll help you anyways.. Y+3z=-7;2x+z=9 so it should be Z+2x=7;3x+4z+2x=4xy so the answer should be 4,2,1 x=4 y=2 z=1

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Which quadrant is the polar coordinate, (3, 280°)

frosja888 [35]

Answer:

the fourth quadrant

Step-by-step explanation:

resolving it into its Cartesian coordinate - x = rcos∅ and y = rsin∅,x = 0.52 and y = -2.95.

x is positive and Y is negative

angle in the fourth quadrant = (360° - ∅°)

7 0

3 years ago

If 11 (n) equals 143 what is n?

UkoKoshka [18]

The value of n that will make the expression equal is 13

<h3>Equations and expression</h3>

Equations are expressions separated by equal sign

Given the equation

11n = 143

Divide both sides by 11 to have;

11n/11 = 143/11

n = 13

Hence the value of n that will make the expression equal is 13

Learn more on linear equation here; brainly.com/question/14323743

#SPJ1

4 0

2 years ago

Simplify each expression using the proper order of operations. please help thank you so much :)

Tasya [4]

Answer:

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

$7^2 - 5* 8+1 = 10$

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

Step-by-step explanation:

<em>Required: Solve the expressions using proper operation order</em>

To solve this, we'll make use of BODMAS

--------------------------------------------------------------------------------------------------------

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26}$

Evaluate all squares and square roots

$\frac{41 - 3*3}{\sqrt{36} * 3 - 26}$

$\frac{41 - 3*3}{6 * 3 - 26}$

Evaluate the numerator (Start by multiplying 3 * 3)

$\frac{41 - 9}{6 * 3 - 26}$

Subtract 9 from 41

$\frac{32}{6 * 3 - 26}$

Evaluate the denominator (Start by multiplying 6 * 3)

$\frac{32}{18 - 26}$

$\frac{32}{-8}$

Divide 32 by -8

-4

Hence;

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

--------------------------------------------------------------------------------------------------------

$12 + 3\sqrt{8} * (9 - 2)$

Start by evaluating the bracket

$12 + 3\sqrt{8} * 7$

Then evaluate the multiplication

$12 + 21\sqrt{8}$

Simplify the square root

$12 + 21\sqrt{4 * 2}$

Split the square root

$12 + 21\sqrt{4} * \sqrt{2}$

Take Square root of 4

$12 + 21 * 2} * \sqrt{2}$

$12 + 42 \sqrt{2}$

Hence;

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

--------------------------------------------------------------------------------------------------------

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5}$

Evaluate 7²

$\frac{28 - (49 + 3)}{-13 + 3 * 5}$

Evaluate all expression in the bracket

$\frac{28 - (52)}{-13 + 3 * 5}$

$\frac{28 - 52}{-13 + 3 * 5}$

Evaluate 3 * 5

$\frac{28 - 52}{-13 + 1 5}$

$\frac{-2 4}{2}$

$-12$

Hence;

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

--------------------------------------------------------------------------------------------------------

$7^2 - 5* 8+1$

Evaluate 7²

$49 - 5* 8+1$

Evaluate 5 * 8

$49 - 40 + 1$

$10$

$7^2 - 5* 8+1 = 10$

--------------------------------------------------------------------------------------------------------

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1$

Evaluate all square root and cube root

$(2 * 4) - (3 * 9) + 1$

Solve the expressions in bracket

$8 - 27 + 1$

$-18$

Hence;

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

7 0

3 years ago

Find the congruence transformation that maps ∆ABC to ∆A’B’C’. Explain your reasoning

aalyn [17]

To flip any of the points to map up correctly to the other points, you would have to do a reflection over the y-axis. The reasoning for this is because you cannot dilate your shape because it won't map over correctly. A translation will not work, mainly because the shape still needs to flip. A rotation will also not work because when you rotate it, the shape will still not map over your new one.

-So your answer to this question would be that only a Reflection over the y-axis will allow the two shapes to map over each other correctly.

7 0

4 years ago

Factor of x^3-x^2-24x-36

Basile [38]

The trial and error method is used to find an initial factor:
If we let f(x) = x³ - x² - 24x - 36 and all we have to do is sub' in values of x until
f(x) = 0, we can use this to find an initial factor by the factor theorem:
f(1) = (1)³ - (1)² - 24(1) - 36 = -60
f(2) = (2)³ - (2)² - 24(2) - 36 = -80
f(5) = (5)³ - (5)² - 24(5) - 36 = -56
*** f(6) = (6)³ - (6)² - 24(6) - 36 = 0 ***

f(6) = 0 so (x - 6) is a factor of f(x).
This means that: f(x) = x³ - x² - 24x - 36 = (x - 6)(ax² + bx + c).
To find a,b and c, use long division (or inspection) to divide x³ - x² - 24x - 36 by x - 6.
The other 2 factors of f(x) can then be found by factorizing the
ax² + bx + c quadratic the way you would with any other quadratic (i.e. by quadratic formula, CTS or inspection).

5 0

3 years ago