First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Answer:
21
Step-by-step explanation:
f(x) = 2x^2 - x
f(-3) = 2*(-3)^2 - (-3)
=2*9 +3
=18 +3
=21
Answer:
s=25
Step-by-step explanation:
I can see the question but if you add a picture maybe i’ll understand it a little more
Step 1 gives you
3*(4x - 2) on the left hand side.
When you remove the brackets what you get is
3*4x - 3*2
12 x - 6 You have to distribute on both sides of the plus sign. The answer is the second one down.
So the answer is 2) <<<< answer.