The quotient may be greater than or less than the dividend or divisor.
When the dividend is less than the divisor, the quotient will be less than one.
When the dividend is greater than the divisor, the quotient will be greater than one.
Answer:
Lets solve it
4x-3 <5
4x<5+3
4x<8
x<8/4
x<2
So yes, two is a solution
Step-by-step explanation:
Answer: the imagine shown below is ur answer :)
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
A box contains 2 blue cards numbered 1 through 2. Let them be named B1 and B2. This box also contains 3 green cards numbered 1 through 3. Let them be named G1, G2 and G3.
The sample space of picking a blue card followed by a green card is
B1, G1
B1, G2
B1, G3
B2, G1
B2, G2
B2, G3
So, there are 6 different outcomes in this sample space.
Answer:
The reflection over the y-axis means that we just multiply the x-value of the coordinates by -1. So we take (4, 0) and get the x-value of 4 and multiply it by -1 which gives us (-4, 0) which is option C.
