Answer:
A bus can carry 22 students and a van can carry 11 students.
Step-by-step explanation:
Let the number of students bus can carry be 'b'.
Let the number of students van can carry be 'v'.
Given:
One High school:
Number of bus = 6
Number of vans = 5
Number of students = 187
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 1
Also Given:
One High school:
Number of bus = 7
Number of vans = 2
Number of students = 176
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 2
Now multiplying equation 2 by 5 we get;

⇒ Equation 3
Now multiplying Equation 1 by 2 we get;

⇒ Equation 4
Subtracting equation 4 from equation 3 we get;

Substituting value of b in equation 2 we get;

Hence A bus can carry 22 students and a van can carry 11 students.
Answer:
its going good, you?
Step-by-step explanation:
Answer:
Hi there!
Your answer is:
Y= 0
X= 9
Step-by-step explanation:
3x=27+3y
3x-10y=27
Solve one of them for Y
I chose the first equation
3x=27+3y
-27
3x-27=3y
/3
x-9 = y
NOW, plug y in the second equation!
3x-10y=27
y= x-9
3x-10y=27
3x-10(x-9) = 27
Solve for x!
3x-10x+90 = 27
-7x + 90 =27
-90
-7x = -63
/-7
x= 9
FINALLY, plug back in x for y equation
y=x-9
x=9
y=9-9
y=0
<span>time for airplane = 11 am to 1 pm = 2 hr
distance travelled by plane = 2a ------- (speed of plane is a mph)
time for auto = 3 am to 1 pm = 10 hr
distance travelled by plane = 10(a – 200)
2a = 10(a – 200)
8a = 2000
a = 250 mph ----- plane
and 250 – 200 = 50 mph ----- auto </span>
$62.50/ 5 tickets= $12.50/ticket.
The rate of cost per ticket is $12.50/ticket~