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Sindrei [870]
3 years ago
10

Figure ABCD is a parallelogram with point C (−4, 1). Figure ABCD is rotated 90° clockwise to form figure A′B′C′D′. What coordina

te would be the output for point C'?
Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0
There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:

R(90 deg) : (X,Y) ---> (-Y,X)

Using the given coordinates:
R(90 deg<span>) : (-4,1) ---> (-1,-4)
</span>
Therefore, Point C' will be located at (-1,-4)
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Answer:

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Step-by-step explanation:

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Note:
The area of a circle with radius r is πr².
An entire circle has a central angle of 360°.

For the sector with radius = (3+4) = 7cm and a central angle of 120°, the area is
A_{1}= \frac{120}{360}*(49 \pi ) = \frac{49}{3} \pi \, cm^{2}

For the sector with radius =  3 cm and a central angle of 120°. the area is
A_{2}= \frac{120}{360} *(9 \pi ) = 3 \pi  \, cm^{2}

The area of the shaded sector (see the figure) is
A=A_{1}-A_{2} = ( \frac{49}{3} -3) \pi  =  \frac{40}{3} \pi  \, cm^{2}

Answer: \frac{40}{3}  \pi  \, cm^{2}


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So - first you gotta put it in the y = mx + b form.


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