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Ilya [14]
3 years ago
13

If KX - 8Y + 4 =0 is parallel to the line who’s equation is 3X -4Y+8 = 0. What is the value of K

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

So - first you gotta put it in the y = mx + b form.


4Y = 3X +8

=> y = 4/3X + 1/2

A parallel line has the same slope. So if 3X - 4Y + 8=0 has a slope of 4/3 then the value of K must also be 4/3

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Answer:

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Step-by-step explanation:

If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...

  y = mx +b . . . . . . . for slope m and y-intercept b

Solving for b gives ...

  b = y -mx . . . . . . . subtract mx from both sides.

The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.

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  b = 6 -4(3) = 6 -12 = -6

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Perpendicular line

  b = 6 -(-1/4)(3) = 6 +3/4 = 27/4

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4 0
2 years ago
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4 0
3 years ago
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Step-by-step explanation:

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Tems11 [23]

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Can I get a thx and brainliest?

7 0
3 years ago
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