Question:
Iliana multiplied 3p – 7 and 2p^2 – 3p – 4. Her work is shown in the table.
Which is the product?
6p^3 + 23p^2 + 9p + 28
6p^3 – 23p^2 – 9p + 28
6p^3 – 23p^2 + 9p + 28
6p^3 + 23p^2 – 9p + 28
Answer:
Option C:
is the correct answer.
Explanation:
The two expressions are
and ![\left2 p^{2}-3 p-4\right](https://tex.z-dn.net/?f=%5Cleft2%20p%5E%7B2%7D-3%20p-4%5Cright)
The product of the expression can be determined by multiplying each of the first term with the second term of the expression, we get,
![(3 p-7)\left(2 p^{2}-3 p-4\right)](https://tex.z-dn.net/?f=%283%20p-7%29%5Cleft%282%20p%5E%7B2%7D-3%20p-4%5Cright%29)
![3 p \cdot 2 p^{2}+3 p(-3 p)+3 p(-4)+(-7) \cdot 2 p^{2}+(-7)(-3 p)+(-7)(-4)](https://tex.z-dn.net/?f=3%20p%20%5Ccdot%202%20p%5E%7B2%7D%2B3%20p%28-3%20p%29%2B3%20p%28-4%29%2B%28-7%29%20%5Ccdot%202%20p%5E%7B2%7D%2B%28-7%29%28-3%20p%29%2B%28-7%29%28-4%29)
Simplifying we have,
![6p^3-9p^2-12p-14p^2+21p+28](https://tex.z-dn.net/?f=6p%5E3-9p%5E2-12p-14p%5E2%2B21p%2B28)
Adding the like terms, we have,
![6 p^{3}-23 p^{2}+9 p+28](https://tex.z-dn.net/?f=6%20p%5E%7B3%7D-23%20p%5E%7B2%7D%2B9%20p%2B28)
Thus, the product of the two expression is ![6 p^{3}-23 p^{2}+9 p+28](https://tex.z-dn.net/?f=6%20p%5E%7B3%7D-23%20p%5E%7B2%7D%2B9%20p%2B28)
Hence, Option C is the correct answer.