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Ivahew [28]
3 years ago
5

Which is the product?

Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

c ;)

Step-by-step explanation:

Luda [366]3 years ago
4 0

Question:

Iliana multiplied 3p – 7 and 2p^2 – 3p – 4. Her work is shown in the table.

Which is the product?

6p^3 + 23p^2 + 9p + 28

6p^3 – 23p^2 – 9p + 28

6p^3 – 23p^2 + 9p + 28

6p^3 + 23p^2 – 9p + 28

Answer:

Option C: 6 p^{3}-23 p^{2}+9 p+28 is the correct answer.

Explanation:

The two expressions are 3 p-7 and \left2 p^{2}-3 p-4\right

The product of the expression can be determined by multiplying each of the first term with the second term of the expression, we get,

(3 p-7)\left(2 p^{2}-3 p-4\right)

3 p \cdot 2 p^{2}+3 p(-3 p)+3 p(-4)+(-7) \cdot 2 p^{2}+(-7)(-3 p)+(-7)(-4)

Simplifying we have,

6p^3-9p^2-12p-14p^2+21p+28

Adding the like terms, we have,

6 p^{3}-23 p^{2}+9 p+28

Thus, the product of the two expression is 6 p^{3}-23 p^{2}+9 p+28

Hence, Option C is the correct answer.

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Step-by-step explanation:

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