X/26=28
•26=•26 (cancels each other out)
X=728
Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
34 x 2 = 17 x 4
answer = 4
Answer:
22
Step-by-step explanation:
We can use the order of operations (PEMDAS), to solve this equation.
We must first multiply and divide, and order. This means we divide 12 by 3 and get 4, then multiply that by 2 and get 8. (30-12÷3×2,30-4×2,30-8). Now we just subtract 8 from 30 and get 22 as our answer.
Answer: Company C
Step-by-step explanation:
A: $150
B: $160
C: $140
D: $170
So Company C has the best rate.
