A) 15% of $32.00 is $4.80.
B) all together he will be paying $36.80.
i hope this helped, good luck!
We need to graph this equation:

Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:

And we divide both sides by 2:

So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:

So the first point is (0,150). Then we can take x=10 and we get:

So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it
Answer:

Step-by-step explanation:
1) First, find the slope of the line. Use the slope formula
. Pick two points on the line and substitute their x and y values into the formula, then solve. I used the points (-5,-4) and (0,-6):
So, the slope of the line is
.
2) Next, use the point-slope formula
to write the equation of the line in point-slope form. (From there, we can convert it to slope-intercept form.) Substitute values for the
,
and
into the formula.
Since
represents the slope, substitute
in its place. Since
and
represent the x and y values of one point on the line, pick any point on the line (any one is fine, it will equal the same thing at the end) and substitute its x and y values in those places. (I chose (0,-6), as seen below.) Then, with the resulting equation, isolate y to put the equation in slope-intercept form:

Answer:
Last one
Step-by-step explanation:
The minus infrot makes it open Down
Its x-... So it - 1
The other number keeps the -
Answer:
Perimeter of A'B'C'D' = 9 units
Step-by-step explanation:
Given:
Perimeter of ABCD = 27 units
Scale factor = 1 / 3
Find:
Perimeter of A'B'C'D'
Computation:
Perimeter of A'B'C'D' = 1/3[Perimeter of ABCD]
Perimeter of A'B'C'D' = 1/3[27]
Perimeter of A'B'C'D' = 9 units