Since the line is parallel to AB, the two slopes are the same
slope of AB = m = (y₂-y₁)/(x₂-x₁)
m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
The origin P(0,0)
y=mx
y= -

x Solution
9514 1404 393
Answer:
a) ∠DAE = 33°; ∠ABD = 57°
b) ∠CEB = 90°
c) ∠ABE = 22°
d) ∠ADE = 15°
Step-by-step explanation:
The diagonals of a rhombus meet at right angles. Each bisects the corner angles at its ends. Adjacent angles are supplementary, opposite angles are congruent, and each diagonal creates two isosceles triangles.
a) ∠DAE = 90° - ∠ADE = 90° -57°
∠DAE = 33°
∠ADE = ∠ABD = 57°
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b) ∠CEB = 90° . . . . . the diagonals meet at right angles
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c) ∠ABE = 44°/2
∠ABE = 22°
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d) ∠ADE = 90° -(1/2)∠DAB = 90° -150°/2
∠ADE = 15°