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3 years ago

Let f(x) = 3x2 - 6x + 2. Find f(-2). A) 20 B) 22 C) 24 D) 26

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

Answer:

D) 26

Step-by-step explanation:

f(x) = 3x^2 - 6x + 2

Let x = -2

f(-2) = 3(-2)^2 - 6(-2) + 2

=3(4) +12+2

= 12 +12+2

=26

FrozenT [24]3 years ago

8 0

For this case we have a function of the form $y = f (x).$

Where:

$f (x) = 3x ^ 2-6x + 2.$

We must find the value of the function when $x = -2.$

Substituting we have:

$f (-2) = 3 (-2) ^ 2-6 (-2) +2\\f (-2) = 3 * 4 + 12 + 2\\f (-2) = 12 + 12 + 2\\f (-2) = 26$

Thus, the value of the function is 26.

Answer:

Option D

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For a standard normal distribution, find the approximate value of p (negative 0.78 less-than-or-equal-to z less-than-or-equal-to

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The approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have $X \sim N(\mu, \sigma)$

(X is following normal distribution with mean $\mu$ and standard deviation $\sigma$ )

then it can be converted to standard normal distribution as

$Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)$

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

$P(Z \leq z) = P(Z < z) )$

Also, know that if we look for Z = z in z-tables, the p-value we get is

$P(Z \leq z) = \rm p \: value$

For this case, we have to find:

$P(-0.78\leq Z \leq 1.16)$

It can be rewritten as:

$P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z < -0.78) \\P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)$

The p-values for Z = 1.16 and Z = -0.78 from the z-table is found as 0.8770 and 0.2177 respectively, and therefore, we get:

$P(-0.78\leq Z \leq 1.16) = P(Z \leq 1.16) - P(Z \leq -0.78)\\P(-0.78\leq Z \leq 1.16) = 0.8770 - 0.2177 = 0.6593$

Thus, the approximate value of P(-0.78 ≤ Z ≤ 1.16) is obtained being 0.6593

Learn more about z-score here:

brainly.com/question/21262765

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2 years ago

Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at the

scZoUnD [109]

Answer:

$\frac{y}{x+y}$

Step-by-step explanation:

The required answer is the rate at which Machine A works when the two machines are combined.

Note: the rate of doing work is express as

$rate=\frac{1}{time taken} \\$

Hence we can conclude that Machine A working rate is

$machine A=\frac{1}{x} \\$ and machine B working rate is

$machine B=\frac{1}{y} \\$

When the two machine works together, the effective working rate is

$\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\$

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

$\frac{1}{x}*combine working rate$

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Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is $\frac{y}{x+y} \\$

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3 years ago