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alexira [117]
3 years ago
13

In a parallel circuit, the current flow through the inductor will be _____.

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

In a parallel circuit, the current flow through the inductor will be <u>90° out of phase with the voltage.</u>

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In order to solve the equation below, you need to change it around so that n is by itself. Write this new equation. Do not inclu
ale4655 [162]
N/6=30
Multiply both sides by 6
n=180
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3 years ago
A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He started at
antiseptic1488 [7]

Answer:

W = 6t + 90

Step-by-step explanation:

Given :

Starting weight = intercept = 90 kg

Weight gained after 8 months = 138 kg

Using the slope intercept relation ;

We can obtain the rate of change, slope ;

y = mt + c

m = slope ; t = time after t months ; c = intercept

y = weight gained after 8 months

138 = 8m + 90

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3 0
3 years ago
Carl has three lengths of cable,
elena-s [515]
Lowest common denominator for 3,4,6 is 12

5/6 = 10/12
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a)
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So you need to use first and second cables

b)
3/12 + 8/12 = 11/12
To reach 1 yard Carl need 1/12 yard cable
6 0
3 years ago
For which problem do you need to regroup 1 ten as 10 ones? Fill in the bubble next to the correct answer. Subtract 16 from 38, s
Kaylis [27]

Answer:

subtract 27 from 85

Step-by-step explanation:

85

-27

———

58

7 cannot be subtracted from 5 so borrow a 10 to make it 7 subtracted from 15 and then the 8 tens becomes 7 tens so 7-2=5

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5 0
3 years ago
Find the equation of the tangent to the circle x2 + y2 = 109 at point (-10,3)
konstantin123 [22]

Answer:

10x - 3y = -109 .

Step-by-step explanation:

x^2 + y^2 = 109

Implicit Differentiation:

2x + 2y.y' = 0

y' = -2x/2y = -x/y

So at the point (-10,3) the gradient of the tangent is -(-10)/3 = 10/3.

Equation of the tangent:

y - y1 = m(x - x1)

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y - 3 = 10/3 x + 100/3

3y - 9 = 10x + 100

-109 + 3y = 10x

10x - 3y = -109  

4 0
3 years ago
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