Answer:
x = 2
Step-by-step explanation:
For quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a).
Here, we have a=2, b=-8, so the axis of symmetry is ...
x = -b/(2a) = -(-8)/(2(2)) = 8/4
x = 2
Answer:
x= 10/13
Step-by-step explanation:
First, we need to put the variable on one side and the constants on another side.
Also a positive and a negative equal a negative. [this is related to +(-8)]
10x+(-8)= -3x+2
+3x +3x
13x-8=2
+8 +8
13x=10
Finally you divide on both sides
13x/13=10/13
x= 10/13
I hope this is right! I tried my best
AB and BC form a right angle at their point of intersection. This means AB is perpendicular to BC.
We are given the coordinates of points A and B, using which we can find the equation of the line for AB.
Slope of AB will be:

Using this slope and the point (2,1) we can write the equation for AB as:

The above equation is in slope intercept form. Thus the y-intercept of AB is 4/3.
Slope of AB is -1/6, so slope of BC would be 6. Using the slope 6 and coordinates of the point B, we can write the equation of BC as:
y - 1 = 6(x - 2)
y = 6x - 12 + 1
y = 6x - 11
Point C lies on the line y = 6x - 11. So if the y-coordinate of C is 13, we can write:
13 = 6x - 11
24 = 6x
x = 4
The x-coordinate of point C will be 4.
Therefore, the answers in correct order are:
4/3 , 6, -11, 4
Answer:
y=-1
Step-by-step explanation:
use point slope formula y-y₁=m(x-x₁)
find m which is slope -1--1/-4--1= 0/-3= 0
plug in the equation and use the first point
y--1=0(x--1)
y=-1