Question

What number am i: when you divide me by five the remainder is four, i have to digits both digits are odd, the sum of my digits is 10?

Answer 1

X is the number
x/5=5a+4
2 digits that are odd
sum is 10

ah, we can make a bit of stuff with the last 2 hints
sum is 10 and are odd
that is
9 and 1
3 and 7
5 and 5
so our possible numbers are
91,19,37,73,55
but 55 is divsible by  5 so it is out

91,19,37,73
test each
91/5 has remainder 1
19/5 has remainder 4
37/5 has remainder 2
73/5 has remainder 3

the number is 19