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belka [17]
3 years ago
6

Construction workers are installing a rectangular, in-ground pool. To start, they dig a rectangular hole in the ground where the

pool will be. The area of the ground that they will be digging up is 276 square feet. The length of the pool is twice the width of the pool.What are the dimensions of the pool? Round to the nearest tenth.
Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

Width = 11.7 feet (To 1 decimal place)

Length = 23.5 feet (To 1 decimal place)

Step-by-step explanation:

w = Width

2w= Length

Area of rectangle = length * width

2w * w = 276

(Simplify expression)

2w² = 276

(Divide both sides by 2)

w² = 138

(Square root both sides to isolate w)

w = √138

w = 11.7473401245

w = 11.7 feet ( 1 decimal place)

2 ×11.7473401245 = 23.4946802489

Length = 23.5 feet (To 1 decimal place)

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