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ikadub [295]
3 years ago
15

solve the equation. Justify each step. 5x - 11 = 34 Plzzz help me this needs to be explained in essay form.

Mathematics
1 answer:
Helga [31]3 years ago
4 0

Answer:

x = 9

Step-by-step explanation:

5x -11 (+11) = 34 (+11)

5x = 45

5x ÷ 5 = 45 ÷ 5

x = 9

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Answer:

Step-by-step explanation:

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3 years ago
Which statement is true?<br> A. .8&gt;.79<br> B. .4&gt;.40<br> C. .76&gt;1.2<br> D. .80&gt;.9
Hitman42 [59]
It is A. Because .8 is the same has saying .80, it is .80>.79, and 80 is greater than 79
7 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Which expression is equivalent to −1.3+(−4.9)+(−2.6) ?
Salsk061 [2.6K]
The correct answer is -3.6. Hope this helps!!
7 0
3 years ago
Need ASAP i will give 10 points
kondor19780726 [428]

Answer:

B) 1

Step-by-step explanation:

There are 8 pairs of data in the table but only 7 points plotted in the graph,

hence there must be 1 point that is missing from the graph.

It turns out that the missing point that was not plotted is (10, 2.5)

5 0
3 years ago
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