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DENIUS [597]
3 years ago
12

-1•f(-8)-4•g(4) help please

Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Answer:

8f-16g

Step-by-step explanation:

We have to simplify each term. So f becomes 8f. Then 4 times 4 becomes 16

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CAN YOU PLSSSSSSSSSSSSSSSSSSS HELP ME WITH THIS
Bond [772]

Answer:

I think its b

Step-by-step explanation:

4 0
3 years ago
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Calculate the approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children.
mixas84 [53]

Answer:

The approximate probability that at least 2 children have been diagnosed with ASD among the 200 selected children is

0.01 or 1%.

Step-by-step explanation:

Number of selected children = 200

The probability of no child been diagnosed with ASD = P(None) = 198/200 = 0.99

Therefore, the probability of at least two children been diagnosed with ASD = 1 - 0.99 = 0.01.

This is the same as:

If 2 children have been diagnosed with ASD,

therefore, the approximate probability that at least 2 children have been diagnosed is:

2/200 = 0.01.  This value is equal to 1%.

The above are summed up in:

The probability of at least one = 1/200 = 0.05

Therefore, the probability of at least two = 0.05 * 2 = 0.01

b) Generally, to find the probability of at least one event happening, we calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none).  For two events happening, the sum of the probability of at least one in two places is deducted from 1 to get the probability of at least two.

4 0
3 years ago
I need help with number 16 i need the answer by 8:45 please. Thank you
Nadusha1986 [10]
Type o ( ii)        =   6 . 25 

Type A ( l^A l ^A    or l ^A i )    = 18 . 75 

Type B   ( l ^b l^b  or l ^ bi )   = 18.75

Type AB ( l ^ A l^ B)    = 56.25 

3 0
3 years ago
Estimate 428,731 - 175,842 = i have no idea
Mariulka [41]
428,731 - 175,842 = 252,889
4 0
3 years ago
Read 2 more answers
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
3 years ago
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