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3 years ago

There are 35 students in a college algebra class. If two fifths of the students are female, how many students are in the class?

Mathematics

1 answer:

sergejj [24]3 years ago

8 0

Answer:

35.

Step-by-step explanation:

You mentioned that there are 35 students in a college algebra class.

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The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacemen

mamaluj [8]

<h2>Answer:</h2>

(a)

The probability is : 1/2

(b)

The probability is : 1/2

<h2>Step-by-step explanation:</h2>

The numbers 1, 2, 3, 4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2) (1,3) (1,4) (1,5)

(2,1) (2,3) (2,4) (2,5)

(3,1) (3,2) (3,4) (3,5)

(4,1) (4,2) (4,3) (4,5)

(5,1) (5,2) (5,3) (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

We know that it could be calculated by using the formula:

$P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is: (4,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

P(A|B)

Hence, based on the data we have:

$P(A\bigcap B)=\dfrac{1}{20}$

( since, the only outcome out of 20 outcomes is: (3,5) )

and

$P(B)=\dfrac{2}{20}$

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

$P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}$

7 0

3 years ago

Can anyone help me in Ptolemy's theorem?

GalinKa [24]

Answer:

Well, I'm not sure what you mean but Ptolemy's Theorem gives a relationship between the side lengths and the diagonals of a cyclic quadrilateral; it is the equality case of Ptolemy's Inequality. Ptolemy's Theorem frequently shows up as an intermediate step in problems involving inscribed figures.

8 0

3 years ago

Sally can detail a car in 50 minutes. Manny does the same job in 35 minutes. How long will it take them to detail a car working

Debora [2.8K]

<u>Answer:</u>

Both Sally ans Manny can detail a car in 20.6 min.

<u>Solution: </u>

Let us assume that together they will take total x minutes to detail the car.

Sally detail the car in 50 min.

So in 1 min sally can detail \left(\frac{1}{50}\right) of the car.

Hence in x min sally can detail \left(\frac{x}{50}\right) of the car.

Manny can detail a car in 35 min.

So in 1 min many can detail \left(\frac{1}{35}\right) of the car.

Hence in x min Manny can detail \left(\frac{x}{35}\right) of the car.

So we can say,

\left(\frac{x}{50}\right)+\left(\frac{x}{35}\right)=1

x\left(\frac{1}{50}+\frac{1}{35}\right)=1

x\left(\frac{7+10}{350}\right)=1

\left(\frac{17 x}{350}\right)=1

$17 x=350$

x=\left(\frac{350}{17}\right)=20.5 8 $\approx$ 20.6

So, both of them can detail a car in 20.6 min.

3 0

3 years ago

Relation sheep between the value of 6s in 6600

forsale [732]

The first 6 is equal to 6,000. The second 6 is equal to 600. 6,000 is 10 times greater than 600.

Hope this Helps!

3 0

4 years ago

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Paige has 1 ½ feet of rope for a project. She only needs 2/3 of it. How much rope does she need?

Grace [21]

Answer:

1 foot

Step-by-step explanation:

1 1/2 = 3/2

2/3*3/2 = 1

4 0

3 years ago

Read 2 more answers