Solution:
Equation of line perpendicular to , x=4 is
y +k=0
As, keep in mind , the equation of line perpendicular to , ax + by +c=0 is b x - a y +c=0
As, given the line perpendicular to, x =4, passes through the point (5,7).
So, y+k =0, passes through (5,7).
→ 7 +k=0
→ k= -7
So, line perpendicular to x=4, which passes through the point (5,7) is →y-7=0 that is y=7.
Option (C) →y=7
Answer:
Your answer is E.
Step-by-step explanation:
Area=L*W*H so try that maybe that will work
Answer:
11. x = 6; y = 6.5
12. x = 2; y = 4
Step-by-step explanation:
In each figure, the hash marks on the lines indicate the parallel lines (marked with red arrows) are equally-spaced. That means the two expressions involving x are equal to each other, and the two expressions involving y are equal to each other.
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11. 2x +1 = x +7
x = 6 . . . . . . . subtract (x+1) from both sides
and
3y -8 = y +5
2y = 13 . . . . add (8-y) to both sides
y = 6.5 . . . . divide by the coefficient of y
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12. x +3 = 3/2x +2
1 = 1/2x . . . . . subtract (x+2)
2 = x . . . . . . . multiply by 2
and
2y -1 = 3y -5
4 = y . . . . . . add (5 -2y)
Answer:
Please see the attached images for full solution.
For question 3, the equation could have also been 3x°= 90°. However, I used ∠ sum of △ since I didnt want to assume that ∠ABC is a right angle.
Likewise for Q4, the polygon looks like a trapezium which means that the 2 horizontal lines are parallel and one could conclude that (3x +3)° +(2x +2)°= 180° (int. ∠s). But since it wasn't clearly indicated that they are parallel, I used the sum of interior angles to find x instead.
