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3 years ago

PLEASE HELP ASAP!!!!!!

Mathematics

1 answer:

Dafna1 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Just multiply the sides. For example, the roses take 8x4=32 feet. if we want to know the area of Zinnias, we multiply the sides 8x12 and remove the roses, which would be 8x12-32=96-32=60 for the Zinnias.

For a)

The roses take 8x4

Zinnias take 8x12 - roses

Snapdragons take 16x12 - roses - zinnias

Petunias take 16x20 - snapdragons - zinnias- roses

b) The entire area of the garden is 20x16=320 square feet

The area of the Zinnias(including roses) is 8x12 = 96 square feet

To get the percent, we divide the smaller number by the bigger number and multiply by 100 or in practice 96/320x100=30%

c) Let's see the progression here. The width progresses in the first rectangle by four 8 to 12, then again by four 12, 16 and again by four 16 to 20, which means that the next rectangle would have a width of 20+4=24. Doing the sale analysis for the height, we get that the increase is with 4 feet at a time or the new rectangle would have a width of 24 and height of 20, which means a total area of 480 feet. We have to subtract all other rectangles or the new area would be 480 - (20x16) = 160 square feet

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mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

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And we can find the limits without any outliers using two deviations from the mean and we got:

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And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

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