What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
Answer:
24y^3/x^5
Step-by-step explanation:
Since 6x and 4x are not in a parentheses, they are not being powered by anything. Therefore, those stay on the numerator side.
Anything to the power of something times another to the power of something is always added together. Since -1 + (-4) is -5, x would end up having a power of -5, which would just make it go on the denominator side with just a power of 5.
Same rule with y follows. This would make it 5+ (-2) = 3. Since this is a positive power, it stays at the numerator side.
Answer:
no solution
Step-by-step explanation:
y = x+1 and y = x + 2 don't touch because they are parallel
if you don't know what parallel means, just search it up, but i can explain it to you:
parallel means same slope or same steepness of line
Hey! This may not be the answer you are looking for obviously. But go on KhanAcademy, they helped me with this when I was in Algebra!
X=4
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