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3 years ago

Saleem wants to create a table of ratios that are equivalent to 2/3. He includes the ratios 4/5 and 5/6.

2 answers:

8 0

No, the ratios are not equivalent to 2/3. To create an equivalent ratio, you need to multiply both numbers in the original ratio by the same number.

I took a test and it said that this was correct. I hope this helps!

svlad2 [7]3 years ago

3 0

No....if you set them up as proportions and cross multiply the sides do not equal

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Three equivalent ratios for each ratio. 18/6 ___ 5/45___ 3/5___

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9:3 3:1 6:2

1:9 2:18 4:36

6:10 12:20 24:40

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3 years ago

Round your answer to the nearest hundredth if necessary. A figure is shown. 8X 44.49 What is the measure, in degrees, of the sha

aivan3 [116]

You can download answer here

tinyurl.com/wpazsebu

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3 years ago

a storage drum in the shape of a cylinder is 3 feet tall and has a diameter of 4 feet. what is the total surface area of the sto

nlexa [21]

Answer:

$SA=62.8\ ft^2$

Step-by-step explanation:

we know that

The surface area of a cylinder is equal to

$SA=2\pi r^{2}+2\pi rh$

we have

$h=3\ ft$

$r=4/2=2\ ft$ ----> the radius is half the diameter

assume

$\pi =3.14$

substitute

$SA=2(3.14)(2)^{2}+2(3.14)(2)(3)$

$SA=62.8\ ft^2$

7 0

3 years ago

Read 2 more answers

Identify the range of the function shown in the graph.

marshall27 [118]

The answer would be D

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3 years ago

An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i

HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = $750+750*0.05=750(1+0.05)$

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

$750*(1+0.05)^10=1221.67$

which we can round to 1222 students enrolled

This means and increase of: $\frac{1222-750}{750} =0.62933$

That is approximately 62.9%

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3 years ago