2 years ago

How many solutions would it have none infinite or one ?

Mathematics

2 answers:

Jlenok [28]2 years ago

8 0

Answer:

Step-by-step explanation:

Vika [28.1K]2 years ago

7 0

Answer:

One

Step-by-step explanation:

You might be interested in

If 2 and 4 each divide q without remainder, which of the following must q divide

Marrrta [24]

Any multiple of 4 would work.

7 0

3 years ago

Can anyone Help me pleasee ?

3241004551 [841]

Answer:

First one

Step-by-step explanation:

.20 is 20% of 100 and there is 5 boxes and 5 times 20 = 100

6 0

2 years ago

What's P squared -1 factorised?

Aleksandr [31]

(p+1) (p-1). solved this on paper . hope it helps .

8 0

3 years ago

Please help, see attachment for equation!

Alekssandra [29.7K]

Answer:

The answer to your question is the last option

Step-by-step explanation:

Quadratic equation

2 = - x + x² - 4

Order the equation from the highest power to the lowest power. Do not consider 2 because it is not consider in the options given.

x² - x - 4 = 0

Identify a, b and c

(1) x² -(1) x - 4 = 0

a = 1 b = -1 c = - 6

Substitution

$\frac{-(-1) +- \sqrt{(-1)^{2} - 4(1)((-4)}}{2(1)}$

3 0

3 years ago

Factor completely<br> -2x^4+6x^3+8x^2

vlada-n [284]

Answer:

-2x²(x + 1)(x - 4)

Step-by-step explanation:

Hello!

Factor:

$-2x^4 + 6x^3 + 8x^2$
$-2x^2(x^2 - 3x - 4)$ Take out GCF

Think: What numbers add up to -3 and multiply to -4?

Answer: -4 and 1

Continue:

$-2x^2(x^2 - 3x - 4)$
$-2x^2(x^2 - 4x + x - 4)$
$-2x^2(x(x - 4) + 1(x - 4))$ Factor by Grouping
$-2x^2(x + 1)(x - 4)$

The complete factored form is -2x²(x + 1)(x - 4)

5 0

2 years ago