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3 years ago

7

Determine if the statement is always, sometimes or never true. The measure of an exterior angle at the vertex of a polygon equal

s the measure of the adjacent interior angle. always

1 answer:

jeka943 years ago

6 0

Answer:

I believe it is never

Step-by-step explanation:

Sorry if I'm wrong ...

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Meow help me pls :(((

pentagon [3]

Answer:

a) 3x-5=16

b) 30cm

Step-by-step explanation:

a) 5(x-1)=2(x+8)

5x-5=2x+16

5x-2x-5=16

3x-5=16

b) solving the equation gives x=7

put x=7 into first line, 5(7-1)=30cm

to check we can place it into second one as well

2(7+8)=30cm

5 0

3 years ago

Find the area of the given triangle to the nearest square unit. Angle a= 30 degrees, b=10, angle B=45 degrees

storchak [24]

Answer:

$A=34\ units^2$

Step-by-step explanation:

Suppose we have a general triangle like the one shown in the figure.

We know the angle A, the angle B and the length b.

$A = 30\°\\\\B = 45\°\\\\b = 10$

By definition I know that the sum of the internal angles of a triangle is always equal to 180 °.

So

$A + B + C = 180\\\\30 + 45 + C = 180$

We solve the equation and thus we find the angle C.

$C = 180 - 30-45\\\\C = 105$

We already know the three triangle angles.

Now we use the sine theorem to calculate the sides c and a.

The sine theorem says that:

$\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}$

Then

$\frac{sin(30)}{a}=\frac{sin(45)}{10}$

$\frac{sin(30)}{\frac{sin(45)}{10}}=a$

$a=7.071$

Also

$\frac{sin(105)}{c}=\frac{sin(45)}{10}$

$\frac{sin(105)}{\frac{sin(45)}{10}}=c$

$c=13.660$

Finally, we use the Heron formula to calculate the triangle area

$A=\sqrt{s(s-a)(s-b)(s-c)}$

Where s is:

$s=\frac{a+b+c}{2}$

Therefore

$s=\frac{7.071+10+13.660}{2}$

$s=15.37$

$A=\sqrt{15.37(15.37-7.071)(15.37-10)(15.37-13.66)}$

$A=34\ units^2$

3 0

3 years ago

In the figure below, Z is the center of the circle. Suppose that OR=4, ST= 4, UZ= 6, and VZ=4x-6. Find the following.

Ann [662]

Answer:

x = 3 units

SV = 2 units

Step-by-step explanation:

In $\odot Z$ QR and ST are chords such that:

QR = ST = 4

That is both the chords are equal in measure.

Equal chords are at equal distance from the center of the circle. Therefore,

VZ = UZ

4x - 6 = 6

4x = 6 + 6

4x = 12

x = 12/4

x = 3 units

Since, perpendicular dropped from the center of the circle bisects the chord.

$\therefore SV = \frac{1}{2} ST$

$\therefore SV = \frac{1}{2} \times 4$

$\therefore SV = 2\: units$

3 0

3 years ago

A student who is 5 ft 6 in. tall measured shadows

irakobra [83]

Answer:

lunar model

there really isnt anything to explain

5 0

3 years ago

The formula A=6s² gives the suface area A of a cube with a side length s. What is the suface area of a cube that has a side leng

Salsk061 [2.6K]

Answer:

150 square inches.

Step-by-step explanation:

Since the surface area of a cube is 6 times the square of the side length of the cube, then that means the surface area of a cube that has a side length of 5 has a surface area of 6 x 5 x 5. 5 times 5 = 25, and 25 x 6 = 150

3 0

2 years ago