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2 years ago

7

Determine if the statement is always, sometimes or never true. The measure of an exterior angle at the vertex of a polygon equal

s the measure of the adjacent interior angle. always

1 answer:

jeka942 years ago

6 0

Answer:

I believe it is never

Step-by-step explanation:

Sorry if I'm wrong ...

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What is 2-1 reversed? A.1 B.-1 C.2 D. -2

vovikov84 [41]

2-1 reversed is turning it around : 1-2 which equals -1 because there is one left over. B is your answer and hoped I helped!

5 0

2 years ago

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El numero de libros vendidos en una tienda aumentó aproximadamente de 6000 a 9000 durante varios meses cual porcientorepresenta

Aleksandr-060686 [28]

Answer:

50%

Step-by-step explanation:

To calculate the percentage of increase, what we must do divide the two quantities, in this way we will be able to know how bigger they are from each other. So:

9000/6000 = 1.5

Now, we subtract those from 1, which would be 100%

1.5 - 1 = 0.5

therefore the increase was 50%

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2 years ago

-8(p - 4) = 96 solve for p

Gwar [14]

Answer:

-8

Step-by-step explanation:

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2 years ago

Divide 6x^2+9x-12/ 3x

uranmaximum [27]

Answer:

2x + 3 - 4/x

Step-by-step explanation:

6x^2 + 9x - 12/ 3x

1. Reduce the expression by cancelling the common factors.

2x^2 + 3x - 4/ x

2. Divide each term in the numerator by the denominator.

2x^2/x + 3x/x - 4/x

3. Simplify each term. Then when you finish to simplify your answwer would be: 2x + 3 - 4/x

i hope its helpful! :D

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2 years ago

[(1/(3+x))-(1/3)] / x<br> Limit 0

Effectus [21]

First find a common denominator and combine the fractions in the numerator:

$\displaystyle\lim_{x\to0}\frac{\dfrac1{3+x}-\dfrac13}x=\lim_{x\to0}\frac{\dfrac3{3(3+x)}-\dfrac{3+x}{3(3+x)}}x=\lim_{x\to0}\frac{3-(3+x)}{3x(3+x)}$

Now simplify and cancel out all the terms that you can:

$\displaystyle\lim_{x\to0}\frac{3-3-x}{3x(3+x)}=-\frac13\lim_{x\to0}\frac1{3+x}$

Since the remaining expression is continuous as a function of $x$ , you can directly substitute to end up with

$\displaystyle-\frac13\lim_{x\to0}\frac1{3+x}=-\frac13\times\frac1{3+0}=-\frac19$

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2 years ago