The formula is (degree)x(pi÷180)
36 x pi ÷ 180
0.63 rad
Answer:
85 minutes.
Step-by-step explanation:
T = Tuesday
M = Monday
T = M - 15, 70 = M - 15, M = 85 minutes.
Since she worked out 15 minutes less than monday on tuesday, you add 15 to 70, since thats what she did on tuesday.
Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
2(x - 3) + 4y - 2(x - y - 3) + 5 =
2x - 6 + 4y - 2x + 2y + 6 + 5 =
6y + 5 <== ur x terms cancel and ur 6's cancel
