Using the Hardy-Weinberg equations, the percentage of carriers of cystic fibrosis is 8.19%.
<h3>What are the Hardy-Weinberg equations?</h3>
The Hardy-Weinberg equations describe the relationship between alleles in a population that is fairly constant.
The Hardy-Weinberg equations are given below as;

Hardy-Weinberg equations
Percentage of carriers = 2pq
Percentage of carriers = 2 * 0.09 * 0.91 * 100 = 8.19%
Therefore, the percentage of carriers of cystic fibrosis is 8.19%.
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Answer:
A fungal cell is an eukaryote with all intracellular, membrane bound organelles. A bacterial cell is basically a prokaryote with a nucleoid. The cell wall composition also varies. It is a lipopolysaccharide layer called peptidoglycan layer in bacteria whereas cell wall of a fungal cell contains complex polysaccharides called chitin and glucans. Bacteria are either autotrophic or heterotrophic whereas fungi are strictly heterotrophic. Bacteria reproduces asexually by binary fission whereas fungi can reproduce either by sexual or by asexual method. Dormant form of fungal cell are called conidiospore or basidiospore or zoospore or ascospore based on their location in hyphae and type of reproduction. In bacteria, dormant forms are called endospores.
Answer:
9/16 black, 3/16 brown, 4/16 white
Explanation:
BD Bd bD bd
BD BBDD BBDd BbDD BbDd
Bd BBDd BBdd BbDd Bbdd
bD BbDD BbDd bbDD bbDd
bd BbDd Bbdd bbDd bbdd
A punnet square can be described as a diagram which is made to predict the genotype as well as the phenotypes of the offsprings of a cross.
To study the epistatis nature of the pigmentation in bear, a punnet square was made and the results of the punnet square are shown above.
The results of the punnet square show that the cross between two bears will have the chances of producing 9/16 black bears, 3/16 brown bears and 4/16 white bears.
Answer:
D) the presence or absence of a Nucleus
Explanation:
A Nucleus is present in a Eukaryotic cell. A Nucleotide is present in a Procaryotic cell. If there is a nucleus present, it is a Eukaryotic cell