Question

Five years from now, the sum of the ages of a women and her daughter will be 40 years. The difference in their present age is 24 years. How old is her Daughter now?

Answer 1

Answer:

Daughter age = 3 years

Step-by-step explanation:

Let x be the age of the women and y be the age of the daughter.

Given:

After five year the sum of the women and daughter age = 40

$(x+5)+(y+5)=40$

At present the sum of the women and daughter age

$x+5+y+5=40$

$x+y+10=40$

$x+y=40-10$

$x+y=30$--------------(1)

So the sum of the present age is $x+y=30$

The difference in their present age is 24 years.

$x-y=24$

$x=24+y$

Now we substitute x value in equation 1.

$(24+y)+y=30$

$24+2y=30$

$2y=30-24$

$2y=6$

$y=\frac{6}{2}$

$y=3\ years$

Therefore, the daughter age is 3 years.