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zimovet [89]
3 years ago
15

Five years from now, the sum of the ages of a women and her daughter will be 40 years. The difference in their present age is 24

years. How old is her Daughter now?
Mathematics
1 answer:
Tomtit [17]3 years ago
7 0

Answer:

Daughter age = 3 years

Step-by-step explanation:

Let x be the age of the women and y be the age of the daughter.

Given:

After five year the sum of the women and daughter age = 40

(x+5)+(y+5)=40

At present the sum of the women and daughter age

x+5+y+5=40

x+y+10=40

x+y=40-10

x+y=30--------------(1)

So the sum of the present age is x+y=30

The difference in their present age is 24 years.

x-y=24

x=24+y

Now we substitute x value in equation 1.

(24+y)+y=30

24+2y=30

2y=30-24

2y=6

y=\frac{6}{2}

y=3\ years

Therefore, the daughter age is 3 years.

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Fiesta28 [93]

Answer:

Uche's pumping rate is <u>300 mL/s</u>.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

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8 0
3 years ago
I need help! Will this would be very appreciated!pls
elena-s [515]

Answer:

No real

solution

Step-by-step explanation:

Firstly, let us check if we would be having a real solution

We start by rewriting the equation

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8x^2 -25x + 24 = 0

We proceed to get the discriminant

Mathematically, we have this as;

D = b^2 - 4ac

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a is the coefficient of x^2 which is 8

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So we have;

D = (-25)^2 - 4(8)(24)

D = 625 - 768 = -143

Since the value of the discriminant is negative, there cannot be real roots

What we have as solution are complex roots

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