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3 years ago

Please help ( Sorry I suck at math lol )

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

5 0

Answer:

It'd be 241

385-(385×(37.4%))= 241

Y_Kistochka [10]3 years ago

3 0

||Answer:D

Step-by-step explanation: 385 * 37.4% = 385 * 0.374= 143.99=144.

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Latanya leaves her house at 12:30 p.M. And bikes at 12 mi/h to Marta's house. She stays at Marta's house for 90 minute. Both gir

Llana [10]

Answer:

Marta's house is 3.10 miles from Latanya's house

Step-by-step explanation:

* Lets explain how to solve the problem

- Latanya leaves her house at 12:30 p.M.

- She bikes at 12 mi/hr to Marta's house

- She stays at Marta's house for 90 minute

- Both girls walk back to latanya's house at 2.5 mi/h

- They arrive at latanya's house at 3:30 p.M.

- We need to know how far is Marta's house from latanya's house

∵ Latanya starts her trip at 12:30 p.M.

∵ She returns her home at 3:30 p.M.

∴ The time of her trip is → 3:30 - 12:30 = 3 hours

- But she stays at at Marta's house for 90 minutes

∵ 1 hour = 60 minutes

∴ 90 minutes = 90 ÷ 60 = 1.5 hours

∴ The time from her house to Marta's house and from Marta's house

to her house is → 3 - 1.5 = 1.5 hours

- Assume that the distance from her house to Marta's house is d

and the time from her house to Marta's house is $t_{1}$ ,

the time from Marta's house to her house is $t_{2}$

∵ Latanya bikes at 12 mi/h to Marta's house

∵ Distance = speed × time

∴ d = 12 × $t_{1}$

∵ Both girls walk back to latanya's house at 2.5 mi/h

∴ d = 2.5 × $t_{2}$

- Equate the two expressions of d

∴ 12 $t_{1}$ = 2.5 $t_{2}$ ⇒ (1)

∵ $t_{1}$ + $t_{2}$ = 1.5

- Subtract $t_{1}$ from both sides

∴ $t_{2}$ = 1.5 - $t_{1}$ ⇒ (2)

- Substitute equation (2) in equation (1)

∴ 12 $t_{1}$ = 2.5(1.5 - $t_{1}$ )

∴ 12 $t_{1}$ = 3.75 - 2.5 $t_{1}$

- Add 2.5 $t_{1}$ to both sides

∴ 14.5 $t_{1}$ = 3.75

- Divide both sides by 14.5

∴ $t_{1}$ = $\frac{15}{58}$ hour

∴ She spends 15/58 hour to bike to Marta's house

- Lets find d

∵ d = 12 $t_{1}$

∴ d = $12*\frac{15}{58}=3.10$ miles

* <em>Marta's house is 3.10 miles from Latanya's house</em>

6 0

3 years ago

A regular hexagon has an apothem measuring 14 cm and an approximate perimeter of 96 cm.

WINSTONCH [101]

Given:
hexagon
apothem of the hexagon: 14 cm
perimeter of the hexagon: 96 cm

Area of the hexagon = [(3√3) / 2] a² ; where a is the measure of the side

hexagon has 6 sides.

Perimeter = 6a
96 cm = 6a
96 cm / 6 = a
16 = a

We can also use the area of a triangle to approximate the area of the hexagon. There are 6 triangles in the hexagon .

Area of a triangle = (height * base) / 2
A = (14 cm * 16 cm) / 2
A = 224 / 2
A = 112 cm²

112 cm² * 6 triangles = 672 cm²

4 0

3 years ago

Read 2 more answers

A quadratic equation is shown: x2 + 18x + 76 = 0 Which of the following is the first correct step to write the above equation in

tia_tia [17]

Answer:

x^2 + 18x + 76 + 5 = 0 + 5

Step-by-step explanation:

The first step is to determine the constant that is needed to be able to write the expression in the desired form. That constant is the square of half the x-term coefficient: (18/2)^2 = 9^2 = 81.

The constant that is present is 76, which is 5 fewer than the needed constant, so the "first step" is to add 5 to both sides of the equation:

x^2 + 18x + 76 + 5 = 0 + 5

Then the next step would be to write the left side as a square:

(x +9)^2 = 5 . . . . . . . p = -9; q= 5

4 0

3 years ago

A ball has been thrown into the air its distance from the ground is given by the function s(t)=-16t^2+96t+100

slega [8]

Answer:

For t=3 sec the velocity change from positive to negative

Step-by-step explanation:

we have

$s(t)=-16t^2+96t+100$

This is the equation of a vertical parabola open downward (the leading coefficient is negative)

where

s(t) is the distance in feet

t is the time in seconds

We know that

To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation

The turning point of the quadratic equation is the vertex

Convert the quadratic equation into vertex form

$s(t)=-16t^2+96t+100$

Factor -16

$s(t)=-16(t^2-6t)+100$

Complete the square

$s(t)=-16(t^2-6t+9)+100+144$

$s(t)=-16(t^2-6t+9)+244$

Rewrite as perfect squares

$s(t)=-16(t-3)^2+244$

The vertex is the point (3,244)

therefore

For t=3 sec the velocity change from positive to negative

8 0

3 years ago

Please help. Thank you.

Trava [24]

Answer:

By the Pythagoras theorem, the hypotenuse (c), is equivalent to:

a^2+ b^2= c^2 where a and b are the other two sides of the right angled triangle, hence c= square root (15^2+ 20^2)= 25

4 0

3 years ago