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spin [16.1K]
3 years ago
9

(-3x +11x-1)+(7x2 - 4x+4)

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

I think the answer might be 4x + 9

Step-by-step explanation:

Solve first bracket

( 8x - 1 ) + ( 10 - 4x )

Take away the brackets.

8x - 1 + 10 - 4x

Minus and add like terms

8x - 4x and -1 + 10

4x + 9

Hopefully that helps:)

Bumek [7]3 years ago
4 0

Step-by-step explanation:

-3x + 11x - 1 + 7x2 - 4x + 4

Solving like terms

7x2 + 4x + 3

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Is this a true, is everything correct and how would you graph it.
Mashutka [201]

Answer:

Step-by-step explanation:

-x -6 ≤ 2 -(3x -4)

-x -6 ≤ 2 -3x + 4

-x ≤ -3x +12

2x ≤ 12

x ≤ 6

You would graph this on a number line with a solid dot on 6. Shade to the left.

3 0
4 years ago
Find the slope of the line through the pair of points.
ANEK [815]
15/8
Bc I just did this
8 0
3 years ago
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A study was conducted to investigate the effectiveness of hypnotism in reducing pain. An SRS of 8 subjects was randomly selected
chubhunter [2.5K]

Answer:

e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

Step-by-step explanation:

Hello!

The study's objective is to test if hypnotism reduces pain.

A sample of n=8 subjects was taken and the pain level was recorded in each subject before and after being hypnotized.

The variable of interest was determined by calculating the difference of pain level after - before hypnosis. This is a paired sample test and the variable can be determined as:

Xd: Difference between pain level felt after hypnosis and pain level felt before hypnosis of a subject.

The sample average and standard deviation obtained were:

Xd= -3

Sd= 3

And the variable is presumed to be approximately normal.

An approximately normal distribution is enough to conduct a paired sample t-test.

If the claim is that hypnosis reduces pain, then the average pain level after hypnosis should be less than the average pain level before hypnosis, then the average difference is expected to be negative, symbolically: μd < 0

The test will be one-tailed and so will be the p-value.

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

So first step is to calculate the value of the statistic under the null hypothesis and then you can calculate the p-value.

H₀: μd ≥ 0

H₁: μd < 0

t_{H_0}= \frac{X_d-Mu_{d}}{\frac{S_d}{n} }= \frac{-0-0}{\frac{3}{\sqrt{8} } } = -2.828= -2.83

The DF of the t-test are n-1= 7

Then you can calculate the p-value as:

P(t₇≤-2.83)= 0.0127

The level of the test is α: 0.01

The decision rule is:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The p-value > α the decision is to not reject the null hypothesis.

Correct option: e. No, the p-value is greater than 0.01, so there is insufficient evidence at the 0.01 level to conclude that pain levels are lower after hypnotism.

I hope this helps!

5 0
3 years ago
Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q
inna [77]
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
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Andre45 [30]
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3 years ago
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