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2 years ago

If the endpoint is (3/2, 1 1/2), and the midpoint is (2/5, -8/5) what is the other endpoint

Mathematics

2 answers:

Tresset [83]2 years ago

6 0

The other endpoint is (-11/10, -71/10)

alukav5142 [94]2 years ago

5 0

Answer:

The answer to your question is ( -7/10, -4 7/10)

Step-by-step explanation:

Data

Enpoint (3/2, 1 1/2) x1 = 3/2 y1 = 1 1/2

Midpoint (2/5, -8/5) xm = 2/5 ym = -8/5

Entpoint 2 ( x, y)

Formula

Xm = (x1 + x2)/2 Solve for x2 x2 = 2xm - x1

Ym = (y1 + y2)/2 Solve for y2 y2 = 2ym - y1

Substitution

x2 = 2(2/5) - 3/2

x2 = 4/5 - 3/2

x2 = (8 - 15)/10

x2 = -7/10

y2 = 2(-8/5) - 1 1/2

y2 = -16/5 - 3/2

y2 = (-32 - 15) / 10

y2 = -47/10 = -4 7/10

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2 years ago

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2 years ago

Y-8= - * - 4 y=-* 4 (3,-5) no solution an infinite number of solutions

muminat

Given:

The system of equation is

$y-8=-\dfrac{1}{3}x-4$

$y=-\dfrac{1}{3}x-4$

To find:

The solution of given system of equations.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

Write the given equation in slope intercept form.

The first equation is

$y-8=-\dfrac{1}{3}x-4$

$y=-\dfrac{1}{3}x-4+8$

$y=-\dfrac{1}{3}x+4$ ...(i)

Here, slope is $-\dfrac{1}{3}$ and y-intercept is 4.

The second equation is

$y=-\dfrac{1}{3}x-4$ ...(i)

Here, slope is $-\dfrac{1}{3}$ and y-intercept is -4.

Since the slopes of both lines are same but the y-intercepts are different, therefore the given equations represent parallel lines.

Parallel lines never intersect each other. So, the given system of equation has no solution.

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