It would be 60 because you add 10, 6 times.
Answer:
Danny will watch all of them on the same day again on August 31
Step-by-step explanation:
Here, we have a word problem.
The shows and frequency of watching are;
Show A Every 2 days
Show B Every 3rd day
Show C Every 5th day
Show D Every 10th day
Danny watched all four shows on August 1, therefore, the day he will watch all four shows can be found by finding the Lowest Common Multiple, LCM of the frequency of his watching each of the shows. That is, the LCM of 2, 3, 5 and 10
Therefore we have, since 10 is the highest frequency and 3 is not a factor of 10, then the LCM that applies to 3 and 10 is 3×10 = 30.
Since the other frequencies are also a factor of 30, then the LCM of 2, 3, 5, and 10 is 30
Therefore, Danny will watch all four shows again on the same day again in 30 days after August 1. That is August (1 + 30) = August 31.
Answer:
I explain down below:
Step-by-step explanation:
First, you divide the combined rectangle into separate parts. Then you find the area of the first rectangle. Then the second and/or third one.
After all the areas have been solved, you add all of the areas together.
Hope this helps!
Answer: 2
Step-by-step explanation: if the rectangles are four then the square is 2
Let us say the price of a table is 
and a price of a chair 
. Using this terminology we can say that the cost of 2 chairs and 5 tables is 
. We have a second equation though, 
from a table being 30 more than the price of a chair. Using this we can solve the system of equations. I think substitution is the quickest way to do this. Plug x from our second equation into the first equation.
This will simplify to the price of a chair is Rs 320. And add Rs 30 to that and we can find that the price of a table is Rs 350.
It is always good to check. So go ahead and check 
to see that the first equation works (we know the second equation works just by eyeballing. And it looks like the cost is Rs 2300! Hooray!
