The first relation gives two y-values for any given x-value (except x=6).
y² +x = 6 . . . . . is not a function
X = -6/5 I hope this helps
Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.
- sinA = opposite/hypotenuse
- cosA = adjacent/hypotenuse
- tanA = opposite/adjacent
Now that we know three basic ratio. Let's check each choices!
This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.
This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.
This choice is correct! As ratio states, tanA = opposite/adjacent.
This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.
This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.
This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.
Answer
Questions can be asked through comment.
Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.
Hope this helps, and Happy Learning! :)
Y=Mx+B -> slope intercept form
The answer would be -3y=-5x-9
Divide the -3 on both sides and you get
y=5/3x+3
Step-by-step explanation:
hope it helps, I have chegg and they seem to have more answers and a lot of topics. you can scan your books bar code and get end of chapter questions
