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3 years ago

8

A line segment has endpoints j (2,4) and L (6,8). The point K is the midpoint of JL. What is an equation of a line perpendicular

of JL and pass through K?
A. Y=- x +10
B. Y=- x - 10
C. Y= x + 2
D. Y= x- 2

1 answer:

algol [13]3 years ago

4 0

C.Y=x+ 2 is the answer to this question

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2 2/7 divided 2 1/2=

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Answer: $\frac{32}{35}$

Step-by-step explanation:

We need to convert the mixed numbers into fractions.

The new numerator will be the sum of the numerator of the fractional part and the product obtained by multiplying the denominator of the fractional part by the whole number part.

The new denominator will the the same denominator of the fractional part.

Then:

$2\ \frac{2}{7}=\frac{2+(2*7)}{7}=\frac{16}{7}$

$2\ \frac{1}{2}=\frac{1+(2*2)}{2}=\frac{5}{2}$

Dividing the fractions, we get:

$\frac{\frac{16}{7}}{\frac{5}{2}}=\frac{16*2}{7*5}=\frac{32}{35}$

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