<img src="https://tex.z-dn.net/?f=%5Csf%2013%2B14%5Ctimes%2011" id="TexFormula1" title="\sf 13+14\times 11" alt="\sf 13+14\times

All categories

Aleksandr-060686 [28]

2 years ago

11" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

nlexa [21]2 years ago

3 0

Answer:

167

Step-by-step explanation:

By BODMAS rule,

13 + 14 x 11

= 13 + ( 14 x 11 )

= 13 + 154

= 167

Note : -

B - Brackets

O - Of

D - Division

M - Multiplication

A - Addition

S - Subtraction

You might be interested in

When running a 100 meter race matt reaches his maximum speed when he is 40 meters from the starting line, and 7 seconds have ela

ch4aika [34]

Answer:

Step-by-step explanation:

time after 40 meters to 80 meters=12-7=5 s

distance=80-40=40 m

max. speed=40/5=8 m/s

4 0

2 years ago

Read 2 more answers

What is the rate of change between (2,2) and (17,7)

ziro4ka [17]

Answer:

$\frac{1}{3} = m$

Step-by-step explanation:

$\frac{-y_1 + y_2}{-x_1 + x_2} = m$

$\frac{-2 + 7}{-2 + 17} = \frac{5}{15} = \frac{1}{3}$

I am joyous to assist you anytime.

6 0

2 years ago

32 + y - 2y? Re write the equation with the variable with the highest exponent first

SVEN [57.7K]

Answer:

-2y^2 + y +32

Step-by-step explanation:

The variable with the highest exponent is y^2

8 0

2 years ago

Question 7 of 7 (1 point) Question Attempt 3 of 3

Neporo4naja [7]

Answer:

To divide, use / instead of \.

Examples: 1+2, 1/3+1/4, 2^3 * 2^2

(x+1)(x+2) (Simplify Example), 2x^2+2y x=5, y=3 (Evaluate Example)

y=x^2+1 (Graph Example), 4x+2=2(x+6) (Solve Example)

Step-by-step explanation:

example

3 0

2 years ago

Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).

vivado [14]

The equation of the line is $y=\frac{1}{4}x-\frac{29}{7}$

Explanation:

The equation of the line is perpendicular to $y=-14 x-8$

The equation is of the form $y=mx+b$ where m=-14

Slope:

The slope of the perpendicular line can be determined using the formula,

$m_1 \cdot m_2=-1$

$-14 \cdot m_2=-1$

$m_2=\frac{1}{14}$

Thus, the slope of the line is $m=\frac{1}{14}$

Equation of the line:

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the slope $m=\frac{1}{14}$ and the point (2,-4), we get,

$y+4=\frac{1}{14}(x-2)$

Simplifying, we get,

$y+4=\frac{1}{14}x-\frac{1}{7}$

$y=\frac{1}{14}x-\frac{1}{7}-4$

$y=\frac{1}{4}x-\frac{29}{7}$

Thus, the equation of the line is $y=\frac{1}{4}x-\frac{29}{7}$

3 0

3 years ago